United States presidential election in Pennsylvania, 1948

United States presidential election in Pennsylvania, 1948
November 2, 1948

Nominee Thomas E. Dewey Harry S. Truman
Party Republican Democratic
Home state New York Missouri
Running mate Earl Warren Alben W. Barkley
Electoral vote 35 0
Popular vote 1,902,197 1,752,426
Percentage 50.93% 46.92%

County results

President before election

Harry S. Truman

Elected President

Harry S. Truman

The 1948 United States presidential election in Pennsylvania took place on November 2, 1948 throughout the continuous 48 states. Voters chose 35 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Republican nominee, New York Governor Thomas E. Dewey, over the Democratic nominee, President Harry Truman. Dewey won Pennsylvania by a margin of 4.01%. As of 2012, this is the last time that a Democrat won the national election without carrying Pennsylvania. It was also the last time until 1968 that a presidential candidate won the election without carrying the state.


United States presidential [1]
Party Candidate Votes Percentage Electoral votes
Republican Thomas E. Dewey 1,902,197 50.93% 35
Democratic Harry Truman 1,752,426 46.92% 0
Progressive Henry Wallace 55,161 1.48% 0
Socialist Norman Thomas 11,325 0.30% 0
Prohibition Claude Watson 10,338 0.28% 0
Militant Workers Farrell Dobbs 2,133 0.06% 0
Industrial Government Edward Teichert 1,461 0.04% 0
Write-ins Write-ins 107 0.00% 0


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