United States presidential election in Pennsylvania, 1836

United States presidential election in Pennsylvania, 1836

November 3 – December 7, 1836

Nominee Martin Van Buren William Henry Harrison Party Democratic Whig Home state New York Ohio Running mate Richard Johnson Francis Granger Electoral vote 30 0 Popular vote 91,457 87,235 Percentage 51.18% 48.82%

President before election Andrew Jackson Democratic Elected President Martin Van Buren Democratic

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The 1836 United States presidential election in Pennsylvania took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 30 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Democratic candidate, Martin Van Buren, over the Whig candidate, William Henry Harrison. Van Buren won Pennsylvania by a margin of 2.36%.

Results

References

State Results of the 1836 U.S. presidential election
Candidates	Martin Van Buren William Henry Harrison Hugh White Daniel Webster Willie Person Mangum
General articles	Election timeline
Local results	Alabama Arkansas Connecticut Delaware Georgia Illinois Indiana Kentucky Louisiana Maine Maryland Massachusetts Michigan Mississippi Missouri New Hampshire New Jersey New York North Carolina Ohio Pennsylvania Rhode Island South Carolina Tennessee Vermont Virginia
Other 1836 elections	House Senate Gubernatorial