United States presidential election in Georgia, 1836

November 3 – December 7, 1836

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The 1836 United States presidential election in Georgia took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for President and Vice President.

Georgia voted for Whig candidate Hugh White over the Democratic candidate, Martin Van Buren. White won Georgia by a margin of 3.6%.

Results

United States presidential election in Georgia, 1836^[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Whig	Hugh White	24,481	51.80%	11
	Democratic	Martin Van Buren	22,778	48.20%	0
Totals			47,259	100.0%	11

State Results of the 1836 U.S. presidential election

Candidates	Martin Van Buren William Henry Harrison Hugh White Daniel Webster Willie Person Mangum

General articles	Election timeline

Local results	Alabama Arkansas Connecticut Delaware Georgia Illinois Indiana Kentucky Louisiana Maine Maryland Massachusetts Michigan Mississippi Missouri New Hampshire New Jersey New York North Carolina Ohio Pennsylvania Rhode Island South Carolina Tennessee Vermont Virginia

Other 1836 elections	House Senate Gubernatorial

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