United States presidential election in Nevada, 1996

United States presidential election in Nevada, 1996
Nevada
November 5, 1996

 
Nominee Bill Clinton Bob Dole Ross Perot
Party Democratic Republican Reform
Home state Arkansas Kansas Texas
Running mate Al Gore Jack Kemp Pat Choate
Electoral vote 4 0 0
States carried 0
Popular vote 203,974 199,244 43,986
Percentage 43.9% 42.9% 9.5%

County Results
  Clinton—<50%
  Dole—<50%
  Dole—50-60%

President before election

Bill Clinton
Democratic

Elected President

Bill Clinton
Democratic

The 1996 United States presidential election in Nevada took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

A swing state, Nevada was narrowly won by incumbent Democratic President Bill Clinton. Clinton took a 43.93% plurality of the popular vote over Republican challenger Bob Dole, who took 42.91%, a victory margin of 1.02%. Reform Party candidate Ross Perot finished in third with 9.47% of the popular vote.[1]

Results

United States presidential election in Nevada, 1996
Party Candidate Votes Percentage Electoral votes
Democratic Bill Clinton (incumbent) 203,974 43.93% 4
Republican Bob Dole 199,244 42.91% 0
Reform Ross Perot 43,986 9.47% 0
N/A None of these Candidates 5,608 1.21% 0
Green Ralph Nader 4,730 1.02% 0
Libertarian Harry Browne 4,460 0.96% 0
Ind. American Howard Phillips 1,732 0.37% 0
Natural Law John Hagelin 545 0.12% 0
Totals 464,279 100.0% 4

References

  1. "1996 Presidential General Election Results". U.S. Election Atlas. Retrieved 30 January 2013.
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