Alford, Florida

Alford, Florida
Town

Location in Jackson County and the state of Florida
Coordinates: 30°41′41″N 85°23′35″W / 30.69472°N 85.39306°W / 30.69472; -85.39306Coordinates: 30°41′41″N 85°23′35″W / 30.69472°N 85.39306°W / 30.69472; -85.39306
Country  United States
State  Florida
County  Jackson
Area
  Total 1.3 sq mi (3.4 km2)
  Land 1.3 sq mi (3.3 km2)
  Water 0 sq mi (0.1 km2)
Elevation 148 ft (45 m)
Population (2000)
  Total 489
Time zone Central (CST) (UTC-6)
  Summer (DST) CDT (UTC-5)
ZIP code 32420
Area code(s) 850
FIPS code 12-00625[1]
GNIS feature ID 0277741[2]

Alford is a town in Jackson County, Florida, United States. It is located in the Florida Panhandle near Marianna. The population was 489 at the 2010 census.[3]

Geography

Alford is located at 30°41′41″N 85°23′35″W / 30.69472°N 85.39306°W / 30.69472; -85.39306 (30.694794, -85.393119).[4]

According to the United States Census Bureau, the town has a total area of 1.3 square miles (3.4 km2), of which 1.3 square miles (3.4 km2) is land and 0.04 square miles (0.10 km2) (1.53%) is water.

Demographics

Historical population
Census Pop.
1920207
19302216.8%
194028328.1%
195037532.5%
19603801.3%
19704025.8%
198054836.3%
1990472−13.9%
2000466−1.3%
20104894.9%
Est. 2015467[5]−4.5%
U.S. Decennial Census[6]

As of the census of 2010, there were 489 people and 202 households in the town.

The population was 48 percent male and 52 percent female. Twenty percent of the population was under 18 and 15.5 percent 65 or over. Ninety-three percent of the population was white and 4 percent Hispanic or Latino.

References

This article is issued from Wikipedia - version of the 10/8/2016. The text is available under the Creative Commons Attribution/Share Alike but additional terms may apply for the media files.