Swiss federal election, 1899

This article is part of a series on the
politics and government of
The 52 electoral districts

Federal elections were held in Switzerland on 26 October 1899. The Free Democratic Party retained its majority in the National Council.[1]

Electoral system

The 147 members of the National Council were elected in 52 single- and multi-member constituencies using a three-round system. Candidates had to receive a majority in the first or second round to be elected; if it went to a third round, only a plurality was required. Voters could cast as many votes as there were seats in their constituency.[2] There was one seat for every 20,000 citizens, with seats allocated to cantons in proportion to their population.[2]


Voter turnout was highest in Schaffhausen (where voting was compulsory) at 86.4% and lowest in Obwalden at 21.3%.

Party Votes % Seats +/–
Free Democratic Party183,21649.784–2
Catholic People's Party76,84520.832+2
Liberal Centre51,76414.120–1
Social Democratic Party35,4889.64+2
Democratic Group18,0034.97–1
Invalid/blank votes33,015
Registered voters/turnout737,69654.5
Source: Mackie & Rose,[3] BFS (seats)


  1. Elections to the National Council 1848–1917: Distribution of seats by party or political orientation BFS
  2. 1 2 Dieter Nohlen & Philip Stöver (2010) Elections in Europe: A data handbook, p1886 ISBN 9783832956097
  3. Thomas T Mackie & Richard Rose (1991) The International Almanac of Electoral History, Macmillan
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